使用Python生成具有给定根的Hermite级数

要生成具有给定根的Hermite级数，请使用Python中的hermite.hermfromroots()方法。该方法返回一个1-D系数数组。如果所有根都是实数，则输出是一个实数组；如果某些根是复数，则输出即使所有结果中的系数都是实数，输出也是复数。参数roots是包含根的序列。

步骤

首先，导入所需的库-

import numpy as np
from numpy.polynomial import hermite as H

使用Python的Numpy库中的hermite.hermfromroots()方法生成具有给定根的Hermite系列。

print("Result...\n",H.hermfromroots((-1,0,1)))

获取数据类型 –

print("\nType...\n",H.hermfromroots((-1,0,1)).dtype)

获取形状 −

print("\nShape...\n",H.hermfromroots((-1,0,1)).shape)

示例

from numpy.polynomial import hermite as H

# To generate a Hermite series with given roots, use the hermite.hermfromroots() method in Python Numpy.
# The method returns a 1-D array of coefficients. If all roots are real then out is a real array, if some of the roots are complex, then out is complex even if all the coefficients in the result are real.

# The parameter roots are the sequence containing the roots.
print("Result...\n",H.hermfromroots((-1,0,1)))

# Get the datatype
print("\nType...\n",H.hermfromroots((-1,0,1)).dtype)

# Get the shape
print("\nShape...\n",H.hermfromroots((-1,0,1)).shape)

输出

Result...
   [0. 0.25 0. 0.125]

Type...
float64

Shape...
(4,)