返回Python中一维向量的点积

要返回一维向量的点积，请在Python中使用numpy.vdot()方法。vdot(a, b)函数与dot(a, b)在处理复数时有所不同。如果第一个参数是复数，则会使用第一个参数的共轭进行点积的计算。vdot与dot在处理多维数组时有所不同：它不执行矩阵乘法，而是先将输入参数展平为1维向量。因此，它只能用于向量。

该方法返回a和b的点积。可以是整数、浮点数或复数，具体取决于a和b的类型。第一个参数是a。如果a是复数，则在计算点积之前会取共轭。b是点积的第二个参数。

步骤

首先，导入所需的库。

import numpy as np

使用array()方法创建两个numpy一维数组 –

arr1 = np.array([2+3j,5+6j])
arr2 = np.array([9+10j,11+12j])

显示数组 –

print("Array1...\n",arr1)
print("\nArray2...\n",arr2)

检查两个数组的尺寸 –

print("\nDimensions of Array1...\n",arr1.ndim)
print("\nDimensions of Array2...\n",arr2.ndim)

检查两个数组的形状 –

print("\nShape of Array1...\n",arr1.shape)
print("\nShape of Array2...\n",arr2.shape)

要返回一维向量的点积，请使用numpy.vdot()方法 –

print("\nResult...\n",np.vdot(arr1, arr2))

示例

import numpy as np

# Creating two numpy One-Dimensional array using the array() method
arr1 = np.array([2+3j,5+6j])
arr2 = np.array([9+10j,11+12j])

# Display the arrays
print("Array1...\n",arr1)
print("\nArray2...\n",arr2)

# Check the Dimensions of both the arrays
print("\nDimensions of Array1...\n",arr1.ndim)
print("\nDimensions of Array2...\n",arr2.ndim)

# Check the Shape of both the arrays
print("\nShape of Array1...\n",arr1.shape)
print("\nShape of Array2...\n",arr2.shape)

# To return the dot product of One-Dimensional vectors, use the numpy.vdot() method in Python.
print("\nResult...\n",np.vdot(arr1, arr2))

输出

Array1...
[2.+3.j 5.+6.j]

Array2...
[ 9.+10.j 11.+12.j]

Dimensions of Array1...
1

Dimensions of Array2...
1

Shape of Array1...
(2,)

Shape of Array2...
(2,)

Result...
(175-13j)