使用Python生成具有给定复根的首一多项式

要生成具有给定复根的首一多项式，请使用Python Numpy中的polynomial.polyfromroots()方法。该方法返回多项式系数的一维数组。如果所有根都是实数，则结果也是实数，否则为复数。参数roots是包含根的序列。

步骤

首先，导入所需的库 –

from numpy.polynomial import polynomial as P

给定复数根 −

j = complex(0,1)
print("Result...\n",P.polyfromroots((-j,j)))

获取数据类型 –

print("\nType...\n",P.polyfromroots((-j, j)).dtype)

获取形状−

print("\nShape...\n",P.polyfromroots((-j, j)).shape)

示例

from numpy.polynomial import polynomial as P

# To generate a monic polynomial with given roots, use the polynomial.polyfromroots() method in Python Numpy.

# The method returns the 1-D array of the polynomial’s coefficients If all the roots are real, then out is also real, otherwise it is complex.

# The parameter roots are the sequence containing the roots.
j = complex(0,1)
print("Result...\n",P.polyfromroots((-j,j)))

# Get the datatype
print("\nType...\n",P.polyfromroots((-j, j)).dtype)

# Get the shape
print("\nShape...\n",P.polyfromroots((-j, j)).shape)

输出

Result...
[1.+0.j 0.+0.j 1.+0.j]

Type...
complex128

Shape...
(3,)