在Python中将一个Hermite_e级数除以另一个

要将一个Hermite_e级数除以另一个，请使用Python Numpy中的polynomial.hermite.hermediv()方法。该方法返回一个表示商和余数的Hermite_e级数系数数组。

返回两个Hermite_e级数c1 / c2的商与余数。参数是从最低阶“项”到最高阶的系数序列，例如[1,2,3]表示系数为P_0 + 2P_1 + 3P_2的级数。参数c1和c2是按从低到高的顺序排列的1-D数组Hermite_e级数系数。

步骤

首先，导入所需的库-

import numpy as np
from numpy.polynomial import hermite as H

创建Hermite_e系数的1-D数组 –

c1 = np.array([53., 30., 52., 7., 6.])
c2 = np.array([1, 2, 3])

展示系数数组 –

print("Array1...\n",c1)
print("\nArray2...\n",c2)

显示数据类型 –

print("\nArray1 datatype...\n",c1.dtype)
print("\nArray2 datatype...\n",c2.dtype)

检查两个数组的维度 –

print("\nDimensions of Array1...\n",c1.ndim)
print("\nDimensions of Array2...\n",c2.ndim)

检查两个数组的形状-

print("\nShape of Array1...\n",c1.shape)
print("\nShape of Array2...\n",c2.shape)

要通过另一个Hermite_e系列来除以一个Hermite_e系列，请使用Python Numpy中的polynomial.hermite.hermediv()方法。

print("\nResult (division)....\n",H.hermediv(c1, c2))

示例

import numpy as np
from numpy.polynomial import hermite_e as H

# Create 1-D arrays of Hermite_e series coefficients
c1 = np.array([53., 30., 52., 7., 6.])
c2 = np.array([1, 2, 3])

# Display the arrays of coefficients
print("Array1...\n",c1)
print("\nArray2...\n",c2)

# Display the datatype
print("\nArray1 datatype...\n",c1.dtype)
print("\nArray2 datatype...\n",c2.dtype)

# Check the Dimensions of both the arrays
print("\nDimensions of Array1...\n",c1.ndim)
print("\nDimensions of Array2...\n",c2.ndim)

# Check the Shape of both the arrays
print("\nShape of Array1...\n",c1.shape)
print("\nShape of Array2...\n",c2.shape)

# To divide one Hermite_e series by another, use the polynomial.hermite.hermediv() method in Python Numpy
print("\nResult (division)....\n",H.hermediv(c1, c2))

输出

Array1...
   [53. 30. 52. 7. 6.]

Array2...
   [1 2 3]

Array1 datatype...
float64

Array2 datatype...
int64

Dimensions of Array1...
1

Dimensions of Array2...
1

Shape of Array1...
(5,)

Shape of Array2...
(3,)

Result (division)....
(array([8., 1., 2.]), array([31., -1.]))