Python 将字符串模式存储为JSON文件
问题描述
我有一段代码,试图在字符串中找到匹配的模式。我想将这些模式存储在JSON文件中,因此我将这些Python字符串转换为JSON格式。但是,它不起作用,我得到了错误的匹配结果,其中不包含正确数量的值。
这是我的Python模式列表的样子:
patterns = [
r"^vol\.(\d+),no\.(\d+)\((\d+)\),p\.(\d+)-(\d+)", #Vol. 12, no. 3, (2009), p. 118-120 r"^vol\.(\d+),no\.(\d+)\((\d+)\),p\.\[(\d+)-(\d+)\]", #vol.1,no.7(2022),p.[1-6]
r"^vol\.(\d+),no\.(\d+)\((\d+)\),p\.(\d+-\d+)-(\d+-\d+)", #vol.10,no.3(2018),p.03015-1-03015-4
r"^vol\.(\d+),no\.([\d-]+)\((\d+)\)p\.(\d+)-(\d+)",
r"^vol(\d+),no\.([\d-]+)\((\d+)\),p\.(\d+)-(\d+)",
r"^vol\.(\d+[a-z]?),no\.(\d+)\((\d+)\),p\.(\d+)-(\d+)", #Vol. 35A, no. 3 (2004), p. 751-759
r"^vol\.(\d+),no\.([\d,]+)\((\d+)\),p\.(\d+)-(\d+)", #Vol. 17, no. 7,8,9,10(2020), p. 573 - 582
r"^vol\.(\d+),no\.([\w]+)\((\d+)\),p\.(\d+)-(\d+)" # vol.7,no.6C(2019),p.38-45
]
这是我在json中的方式:
{
"patterns": [
"^vol\\.(\\d+),no\\.(\\d+)\\((\\d+)\\),p\\.(\\d+)-(\\d+)",
"^vol\\.(\\d+),no\\.(\\d+)\\((\\d+)\\),p\\.\\[(\\d+)-(\\d+)\\]",
"^vol\\.(\\d+),no\\.(\\d+)\\((\\d+)\\),p\\.(\\d+-\\d+)-(\\d+-\\d+)",
"^vol\\.(\\d+),no\\.[\\d-]+\\((\\d+)\\)p\\.(\\d+)-(\\d+)",
"^vol(\\d+),no\\.[\\d-]+\\((\\d+)\\),p\\.(\\d+)-(\\d+)",
"^vol\\.(\\d+[a-z]?),no\\.(\\d+)\\((\\d+)\\),p\\.(\\d+)-(\\d+)",
"^vol\\.(\\d+),no\\.[\\d,]+\\((\\d+)\\),p\\.(\\d+)-(\\d+)",
"^vol\\.(\\d+),no\\.[\\w]+\\((\\d+)\\),p\\.(\\d+)-(\\d+)"
]
}
这是我使用它们的示例,并帮助打印出错误:
config_filename = "configuration\most_used_patterns_Vol_Iss_Year_Page.json"
config = load_config(config_filename)
if config is not None:
patterns = config.get('patterns', [])
for pattern in patterns:
match = re.match(pattern, row)
if match:
print(pattern)
print(match)
groups = match.groups()
print(groups[0])
print(groups[1])
print(groups[2])
print(groups[3])
volume, issue, year, start_page, end_page = match.groups()
输出:
^vol\.(\d+),no\.[\d,]+\((\d+)\),p\.(\d+)-(\d+)$
<re.Match object; span=(0, 29), match='vol.37,no.6,7(1987),p.370-377'>
37
1987
370
377
ValueError: not enough values to unpack (expected 5, got 4)
在我没有从JSON文件中读取它们,而是直接在Python中以我提到的形式拥有它们时,它是可以工作的。有人能解释一下这些JSON文件出了什么问题,或者也许使用不同类型的文件来存储这些字符串模式是更好的选择。
解决方案
似乎你的JSON序列化出了些问题。
最好使用Python从输入数据中创建JSON:
patterns = [
r"^vol\.(\d+),no\.(\d+)\((\d+)\),p\.(\d+)-(\d+)", #Vol. 12, no. 3, (2009), p. 118-120 r"^vol\.(\d+),no\.(\d+)\((\d+)\),p\.\[(\d+)-(\d+)\]", #vol.1,no.7(2022),p.[1-6]
r"^vol\.(\d+),no\.(\d+)\((\d+)\),p\.(\d+-\d+)-(\d+-\d+)", #vol.10,no.3(2018),p.03015-1-03015-4
r"^vol\.(\d+),no\.([\d-]+)\((\d+)\)p\.(\d+)-(\d+)",
r"^vol(\d+),no\.([\d-]+)\((\d+)\),p\.(\d+)-(\d+)",
r"^vol\.(\d+[a-z]?),no\.(\d+)\((\d+)\),p\.(\d+)-(\d+)", #Vol. 35A, no. 3 (2004), p. 751-759
r"^vol\.(\d+),no\.([\d,]+)\((\d+)\),p\.(\d+)-(\d+)", #Vol. 17, no. 7,8,9,10(2020), p. 573 - 582
r"^vol\.(\d+),no\.([\w]+)\((\d+)\),p\.(\d+)-(\d+)" # vol.7,no.6C(2019),p.38-45
]
import json
with open("patterns.json", "w") as f:
json.dump({"patterns": patterns}, f, indent=2)
这应该给你一个包含以下内容的适当的JSON文件:
{
"patterns": [
"^vol\\.(\\d+),no\\.(\\d+)\\((\\d+)\\),p\\.(\\d+)-(\\d+)",
"^vol\\.(\\d+),no\\.(\\d+)\\((\\d+)\\),p\\.\\[(\\d+)-(\\d+)\\]",
"^vol\\.(\\d+),no\\.(\\d+)\\((\\d+)\\),p\\.(\\d+-\\d+)-(\\d+-\\d+)",
"^vol\\.(\\d+),no\\.([\\d-]+)\\((\\d+)\\)p\\.(\\d+)-(\\d+)",
"^vol(\\d+),no\\.([\\d-]+)\\((\\d+)\\),p\\.(\\d+)-(\\d+)",
"^vol\\.(\\d+[a-z]?),no\\.(\\d+)\\((\\d+)\\),p\\.(\\d+)-(\\d+)",
"^vol\\.(\\d+),no\\.([\\d,]+)\\((\\d+)\\),p\\.(\\d+)-(\\d+)",
"^vol\\.(\\d+),no\\.([\\w]+)\\((\\d+)\\),p\\.(\\d+)-(\\d+)"
]
}
将这段内容读回Python中并与原始数据进行比较,应该可以证明它被正确存储。