在Python中将一个Hermite级数除以另一个级数

要将一个Hermite级数除以另一个级数，在Python的Numpy库中使用polynomial.hermite.hermdiv()方法。该方法返回一个由Hermite级数系数表示的商和余数的数组。返回两个Hermite级数c1 / c2的商与余数。参数是从最低阶“项”到最高阶的系数序列，例如，[1,2,3]表示级数P_0 + 2*P_1 + 3*P_2。参数c1和c2是按照从低到高的顺序排列的Hermite级数系数的1维数组。

步骤

首先，导入所需的库-

import numpy as np
from numpy.polynomial import hermite as H

创建Hermite系数的一维数组−

c1 = np.array([53., 30., 52., 7., 6.])
c2 = np.array([1, 2, 3])

显示系数数组 –

print("Array1...\n",c1)
print("\nArray2...\n",c2)

显示数据类型 −

print("\nArray1 datatype...\n",c1.dtype)
print("\nArray2 datatype...\n",c2.dtype)

检查两个数组的维度 –

print("\nDimensions of Array1...\n",c1.ndim)
print("\nDimensions of Array2...\n",c2.ndim)

检查两个数组的形状 –

print("\nShape of Array1...\n",c1.shape)
print("\nShape of Array2...\n",c2.shape)

要将一个Hermite系列除以另一个，可以使用Python中的polynomial.hermite.hermdiv()方法。 Numpy −

print("\nResult (division)....\n",H.hermdiv(c1, c2))

示例

import numpy as np
from numpy.polynomial import hermite as H

# Create 1-D arrays of Hermite series coefficients
c1 = np.array([53., 30., 52., 7., 6.])
c2 = np.array([1, 2, 3])

# Display the arrays of coefficients
print("Array1...\n",c1)
print("\nArray2...\n",c2)

# Display the datatype
print("\nArray1 datatype...\n",c1.dtype)
print("\nArray2 datatype...\n",c2.dtype)

# Check the Dimensions of both the arrays
print("\nDimensions of Array1...\n",c1.ndim)
print("\nDimensions of Array2...\n",c2.ndim)

# Check the Shape of both the arrays
print("\nShape of Array1...\n",c1.shape)
print("\nShape of Array2...\n",c2.shape)

# To divide one Hermite series by another, use the polynomial.hermite.hermdiv() method in Python Numpy
print("\nResult (division)....\n",H.hermdiv(c1, c2))

输出

Array1...
   [53. 30. 52. 7. 6.]

Array2...
   [1 2 3]

Array1 datatype...
float64

Array2 datatype...
int64

Dimensions of Array1...
1

Dimensions of Array2...
1

Shape of Array1...
(5,)

Shape of Array2...
(3,)

Result (division)....
   (array([0., 1., 2.]), array([1., 1.]))