在Python中通过一个独立变量乘以勒让德级数

要将勒让德级数c乘以自变量x，请使用Python Numpy中的polynomial.laguerre.legmulx()方法。该方法返回表示乘法结果的数组。返回两个勒让德级数的差c1 – c2。参数是按照从低阶到高阶排序的系数序列，即[1,2,3]表示P_0 + 2P_1 + 3P_2的级数。参数c是一个按照从低到高排序的一维数组，包含勒让德级数的系数。

步骤

首先，导入所需的库−

import numpy as np
from numpy.polynomial import laguerre as L

创建一个数组-

c = np.array([1, 2, 3])

显示数组 −

print("Our Array...\n",c)

检查尺寸 −

print("\nDimensions of our Array...\n",c.ndim)

获取数据类型 –

print("\nDatatype of our Array object...\n",c.dtype)

获取形状 –

print("\nShape of our Array object...\n",c.shape)

要将Legendre级数c乘以自变量x，在Python Numpy中使用polynomial.laguerre.legmulx() 方法：

print("\nResult....\n",L.legmulx(c))

示例

import numpy as np
from numpy.polynomial import legendre as L

# Create an array
c = np.array([1, 2, 3])

# Display the array
print("Our Array...\n",c)

# Check the Dimensions
print("\nDimensions of our Array...\n",c.ndim)

# Get the Datatype
print("\nDatatype of our Array object...\n",c.dtype)

# Get the Shape
print("\nShape of our Array object...\n",c.shape)

# To multiply the Legendre series c by x, where x is the independent variable, use the polynomial.laguerre.legmulx() method in Python Numpy
print("\nResult....\n",L.legmulx(c))

输出

Our Array...
   [1 2 3]

Dimensions of our Array...
1

Datatype of our Array object...
int64

Shape of our Array object...
(3,)

Result....
   [0.66666667 2.2 1.33333333 1.8 ]