在Python中将一个Legendre级数除以另一个

在Python中将一个Legendre级数除以另一个

要将一个Legendre级数除以另一个,请使用Python中的polynomial.legendre.legdiv()方法。该方法返回表示商和余数的Legendre级数系数的quo和rem。

返回两个Legendre级数c1 / c2的带余除法。参数是从最低到最高阶的系数序列,例如,[1,2,3]表示系列P_0 + 2P_1 + 3P_2。参数c1和c2是按照从低到高的顺序排列的1-D数组。

步骤

首先,导入所需的库−

import numpy as np
from numpy.polynomial import laguerre as L

创建Legendre级数系数的一维数组 –

c1 = np.array([2,3,4])
c2 = np.array([4,3,2])

显示系数数组 −

print("Array1...\n",c1)
print("\nArray2...\n",c2)

显示数据类型 −

print("\nArray1 datatype...\n",c1.dtype)
print("\nArray2 datatype...\n",c2.dtype)

检查两个数组的尺寸 –

print("\nDimensions of Array1...\n",c1.ndim)
print("\nDimensions of Array2...\n",c2.ndim)

检查两个数组的形状-

print("\nShape of Array1...\n",c1.shape)
print("\nShape of Array2...\n",c2.shape)

将一个Legendre级数除以另一个,使用Python中的polynomial.legendre.legdiv()方法 Numpy −

print("\nResult (division)....\n",L.legdiv(c1, c2))

示例

import numpy as np
from numpy.polynomial import legendre as L

# Create 1-D arrays of Legendre series coefficients
c1 = np.array([2,3,4])
c2 = np.array([4,3,2])

# Display the arrays of coefficients
print("Array1...\n",c1)
print("\nArray2...\n",c2)

# Display the datatype
print("\nArray1 datatype...\n",c1.dtype)
print("\nArray2 datatype...\n",c2.dtype)

# Check the Dimensions of both the arrays
print("\nDimensions of Array1...\n",c1.ndim)
print("\nDimensions of Array2...\n",c2.ndim)

# Check the Shape of both the arrays
print("\nShape of Array1...\n",c1.shape)
print("\nShape of Array2...\n",c2.shape)

# To divide one Legendre series by another, use the polynomial.legendre.legdiv() method in Python Numpy
print("\nResult (division)....\n",L.legdiv(c1, c2))

输出

Array1...
   [2 3 4]

Array2...
   [4 3 2]

Array1 datatype...
int64

Array2 datatype...
int64

Dimensions of Array1...
1

Dimensions of Array2...
1

Shape of Array1...
(3,)

Shape of Array2...
(3,)

Result (division)....
   (array([2.]), array([-6., -3.]))

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