在Python中从一个Hermite_e级数中减去另一个

要从一个Hermite_e级数中减去另一个，请使用Python Numpy中的polynomial.hermite.hermesub()方法。该方法返回一个表示它们之差的数组，表示差值的Hermite_e级数。返回两个Hermite_e级数c1 – c2的差。系数序列是从最低次项到最高次项，即，[1,2,3]表示级数P_0 + 2P_1 + 3P_2。参数c1和c2是按从低到高顺序排列的Hermite_e级数系数的1-D数组。

步骤

首先，导入所需的库−

import numpy as np
from numpy.polynomial import hermite_e as H

创建Hermite_e系数的1-D数组 –

c1 = np.array([1,2,3])
c2 = np.array([3,2,1])

显示系数的数组 –

print("Array1...\n",c1)
print("\nArray2...\n",c2)

显示数据类型 −

print("\nArray1 datatype...\n",c1.dtype)
print("\nArray2 datatype...\n",c2.dtype)

检查两个数组的尺寸 –

print("\nDimensions of Array1...\n",c1.ndim)
print("\nDimensions of Array2...\n",c2.ndim)

检查两个数组的形状−

print("\nShape of Array1...\n",c1.shape)
print("\nShape of Array2...\n",c2.shape)

要将一个Hermite_e系列减去另一个Hermite_e系列，可以使用Python Numpy中的polynomial.hermite.hermesub()方法。

print("\nResult (difference)....\n",H.hermesub(c1, c2))

示例

import numpy as np
from numpy.polynomial import hermite_e as H

# Create 1-D arrays of Hermite_e series coefficients
c1 = np.array([1,2,3])
c2 = np.array([3,2,1])

# Display the arrays of coefficients
print("Array1...\n",c1)
print("\nArray2...\n",c2)

# Display the datatype
print("\nArray1 datatype...\n",c1.dtype)
print("\nArray2 datatype...\n",c2.dtype)

# Check the Dimensions of both the arrays
print("\nDimensions of Array1...\n",c1.ndim)
print("\nDimensions of Array2...\n",c2.ndim)

# Check the Shape of both the arrays
print("\nShape of Array1...\n",c1.shape)
print("\nShape of Array2...\n",c2.shape)

# To subtract one Hermite_e series to another, use the polynomial.hermite.hermesub() method in Python Numpy
print("\nResult (difference)....\n",H.hermesub(c1, c2))

输出

Array1...
   [1 2 3]

Array2...
   [3 2 1]

Array1 datatype...
int64

Array2 datatype...
int64

Dimensions of Array1...
1

Dimensions of Array2...
1

Shape of Array1...
(3,)

Shape of Array2...
(3,)

Result (difference)....
   [-2. 0. 2.]