C++ bitset any()函数

C++ bitset any()函数用于测试bitset中是否至少有一个位被设置。它返回一个布尔值，即true或false。

语法

bool any();

参数

它不接受任何参数。

返回值

它返回一个布尔值，可以是0或1。

示例1

#include <iostream>
#include <bitset>
using namespace std;
int main()
{
 // initialization
bitset<4> b1(string("1100"));
bitset<6> b2(string("000000"));
// function to check if any of
 // its bits are set or not
bool result1 = b1.any();
if (result1)
cout<< b1 << " has a minimum of one-bit set"
<<endl;
else
cout<< b1 << " does not have any bits set"
<<endl;
// function to check if any of
// its bits are set or not
bool result2 = b2.any();
if (result2)
cout<< b2 << "  has a minimum of one-bit set"
<<endl;
else
cout<< b2 << " does not have any bits set"
<<endl;
return 0;
}

输出：

1100 has a minimum of one-bit set
000000 does not have any bits set

示例2

#include <iostream>
#include <bitset>
using namespace std;
int main()
{
bitset<4> b1(string("1100"));
bitset<4> b2(string("00"));
bool result1 = b1.any();
if (result1)
cout<< b1.count() << " has a minimum of one-bit set"
<<endl;
else
cout<< b1.count() << " does not have any bits set"
<<endl;
bool result2 = b2.any();
if (result2)
cout<< b2.count() << " has a minimum of one-bit set"
<<endl;
else
cout<< b2.count() << " does not have any bits set"
<<endl;
return 0;
}

输出:

2 has a minimum of one-bit set
0 does not have any bits set