Java 如何确认给定的四个点是否形成一个正方形
正方形是一个二维形状,它有四条相等长度的边。正方形的对边是平行的,并且它的四个内角都是直角,对角线长度相等。在本文中,我们将会检查如何确认给定的四个点是否形成一个正方形。
我们将会给定一个正方形,它有四个点,即A,B,C,D,如图所示 –
public class Main{
//main method
public static void main(String[] args){
//declaring variables
int x1=3, x2=4, x3=7, x4=1;
int y1=7, y2=3, y3=8, y4=9;
double d1, d2, d3, d4, d5, d6;
//applyinng logic
d1 = (x2 - x1) * (x2 - x1) + (y2 - y1) * (y2 - y1);
d2 = (x3 - x2) * (x3 - x2) + (y3 - y2) * (y3 - y2);
d3 = (x4 - x3) * (x4 - x3) + (y4 - y3) * (y4 - y3);
d4 = (x1 - x4) * (x1 - x4) + (y1 - y4) * (y1 - y4);
d5 = (x4 - x2) * (x4 - x2) + (y4 - y2) * (y4 - y2);
d6 = (x3 - x1) * (x3 - x1) + (y3 - y1) * (y3 - y1);
if (d1 == 0 || d2 == 0 || d3 == 0 || d4 == 0 || d5 == 0 || d6 == 0){
System.out.println("Given four points do not form a square");
}
else if (d1 == d2 && d2 == d3 && d3 == d4 && d5 == d6){
//prints if four points form square
System.out.println("Given four points form a square");
} else {
//prints if four points do not form square
System.out.println("Given four points do not form a square");
}
}
}
输出
Given four points do not form a square
方法1:通过使用用户定义的方法
在这种方法中,将分配点值。然后通过传递给定的值调用一个用户定义的方法,并根据算法找到给定的四个点是否形成正方形。
示例
public class Main{
//main method
public static void main(String[] args){
//creating objects of Point
Point p1 = new Point(20, 20);
Point p2 = new Point( 20, 10 );
Point p3 = new Point(10, 10 );
Point p4 = new Point( 10, 20 );
//calling user defined method
if(isSquare(p1, p2, p3, p4)==true){
//print if four points form a square
System.out.println("Given four points form a square");
}
else{
//print if points does not form a square
System.out.println("Given four points do not form a square");
}
}
// Declaring Point class
static class Point{
int x, y;
public Point(int x, int y){
this.x = x;
this.y = y;
}
};
//function to find square of distance from point 'p' to point 'q'
static int distSq(Point p, Point q){
return (p.x - q.x) * (p.x - q.x) + (p.y - q.y) * (p.y - q.y);
}
//user defined method
static boolean isSquare(Point p1, Point p2, Point p3, Point p4){
int d1 = distSq(p1, p2);
int d2 = distSq(p2, p3);
int d3 = distSq(p3, p4);
int d4 = distSq(p4, p1);
int d5 = distSq(p1, p3);
int d6 = distSq(p2, p4);
if (d1 == 0 || d2 == 0 || d3 == 0 || d4 == 0 || d5 == 0 || d6 == 0)
return false;
if (d1 == d2 && d2 == d3 && d3 == d4 && d5 == d6){
//it returns true if (p1, p2, p3, p4) form a square
return true;
}
//it returns false if (p1, p2, p3, p4) do not form a square
return false;
}
}
输出
Given four points form a square
在本文中,我们使用Java编程语言探讨了不同的方法,以检查一条线是否与一个圆相接触、相交或位于圆外。