PHP math acos()函数

PHP math acos()函数

The acos()函数是一个有用的预定义PHP函数,用于计算三角学问题。它用于以弧度形式找到一个数的反余弦。

注意:acos(-1)返回Pi的值。

语法

acos(number);
参数 描述 必需/可选
数字 指定一个范围在-1到1的数字。 必需

示例1

<?php
num=0;
echo "Your number is :".num;
echo "<br>"."By using 'acos()' function your number is :".(acos($num));
?>

输出结果:

Your number is :0
By using 'acos()' function your number is :1.5707963267949

示例2

<?php
num=1;
echo "Your number is :".num;
echo "<br>"."By using 'acos()' function your number is :".(acos($num));
?>

输出:

Your number is :1
By using 'acos()' function your number is :0

示例3

<?php
num=2;
echo "Your number is :".num;
echo "<br>"."By using 'acos()' function your number is :".(acos($num));
echo "<br>"." Note : Your number is outside the range [-1,1]";
?>

输出:

Your number is :2
By using 'acos()' function your number is :NAN
Note : Your number is outside the range [-1,1]

示例4

<?php
num=(0.64);
echo "Your number is :".num;
echo "<br>"."By using 'acos()' function your number is :".(acos($num));
?>

输出:

Your number is :0.64
By using 'acos()' function your number is :0.87629806116834

示例5

<?php
num=(-0.4);
echo "Your number is :".num;
echo "<br>"."By using 'acos()' function your number is :".(acos($num));
?>

输出:

Your number is :-0.4
By using 'acos()' function your number is :1.9823131728624

示例6

<?php
num=(-1);
echo "Your number is :".num;
echo "<br>"."By using 'acos()' function your number is :".(acos($num));
?>

输出:

Your number is :-1
By using 'acos()' function your number is :3.1415926535898

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